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Mathematics 8 Online
OpenStudy (anonymous):

What is the equation of the following graph? Answers: (x+2)2/9+(y+2)2/4=1 (x-2)2/4+(y-2)2/9=1 (x-2)2/9-(y-2)2/4=1 (x-2)2/9+(y-2)2/4=1

OpenStudy (anonymous):

OpenStudy (rsadhvika):

it is translated +2 right, +2 up

OpenStudy (rsadhvika):

so you must have something like :- (x-2)^2/a^2 + (y-2)^2/b^2 = 1

OpenStudy (ddcamp):

First part: Where is the center of the ellipse? Since the major axis is horizontal, the standard form is: \[\frac{ (x-h)^2 }{ a^2 } + \frac{ (y-k)^2 }{ b^2 } = 1\] Where (h,k) is the center, a is half the length of the major axis, and b is half the length of the minor axis.

OpenStudy (anonymous):

I got D

OpenStudy (rsadhvika):

you got it right !

OpenStudy (ddcamp):

Yup

OpenStudy (anonymous):

Awesome!!!

OpenStudy (rsadhvika):

you're awesome ! keep up the good work (:

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