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What is the equation of the following graph? Answers: (x+2)2/9+(y+2)2/4=1 (x-2)2/4+(y-2)2/9=1 (x-2)2/9-(y-2)2/4=1 (x-2)2/9+(y-2)2/4=1
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it is translated +2 right, +2 up
so you must have something like :- (x-2)^2/a^2 + (y-2)^2/b^2 = 1
First part: Where is the center of the ellipse? Since the major axis is horizontal, the standard form is: \[\frac{ (x-h)^2 }{ a^2 } + \frac{ (y-k)^2 }{ b^2 } = 1\] Where (h,k) is the center, a is half the length of the major axis, and b is half the length of the minor axis.
I got D
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you got it right !
Yup
Awesome!!!
you're awesome ! keep up the good work (:
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