Find the Absolute Value with solution set. then Graph 1.) 2x-3y=2 4x+5y=26 2.) x+y-6=0 3x-5y-34=0
Absolute Value with solution set? I'm afraid I don't understand that :D
maybe its my writing, but can you help me find the absolute value of both? and then graph
Absolute value? Not sure what that is... as for the solution, I guess I can help out there...
Quite frankly, I don't know what these mean... you're using an entirely different method...
Not one that I've ever heard of :D
5x-3y-16=0 4x-5y-5=0 Solution Set x| 2 |5 5(2)-36-16 5(5)-3y-16=0 y|-2 |3 10-3y-16 25-36-16=0 3y=16-10 36=16-25 3y=6 3y=9 3 3 y=-2 3 3 y=3 x|5|0 4(5)-5y-5=0 -5y-5=0 y|3|-1 20-5y=0 -5y=5 -5y=5-20 -5 -5 y=-1 -5=-15 -5 -5 y=3
can you help me get the absolute value of this 5x-3y-16=0 4x-5y-5=0?
Absolute value? I don't know what that means in this context.
i cant seem to understand how they get this x| 2 |5 & x|5|0 y|-2 |3 y|3|-1
LOL me neither... this is a method I am unfamiliar with... I guess the best I could do is attempt to solve it in the conventional way?
and then graph?
Yeah, graphing lines takes practice, but it's easy to get used to.
ok then
Well, can you solve the system? Using substitution.
Faulty... though I admire your effort... extraordinary :D
lol i think, i really need to find the absolute value 1st, thats what my teacher recommend to use.
You'll need to consult with someone else for that.. I really don't know that method... sorry T.T
ok then, switching to google :D
but can you show me how to graph this?
Well, graphing lines involves finding two points on that line, and then just connecting them to form a line :)
It can actually be any two points, but the simplest is finding what are called the "intercepts". Heard that word before?
nope
Okay... an x-intercept is the point where the line intersects the x-axis. a y-intercept is the point where the lint intersects the y-axis. To get the x-intercept simply set y = 0, and solve for x. The x-intercept would be (x , 0) but you have to solve for x.... To get the y-intercept, set x = 0, and solve for y. The y-intercept would be (0 , y), after you solve for y.
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