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Mathematics 15 Online
OpenStudy (anonymous):

Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x^2 – 6x + 3 = 0 A. three real-number roots B. two real-number roots C. one real-number root D. no real-number roots

OpenStudy (anonymous):

\[\Delta=b^2-4ac\] \[a=3\] \[b=-6\] \[c=3\]

OpenStudy (anonymous):

if the discriminant is less than 0, there are no real solutions if the discriminant is equal to 0, there is one real solution if the discriminant is larger than 0, there are 2 real solutions

OpenStudy (anonymous):

wich one is it

OpenStudy (anonymous):

try working it out for yourself

OpenStudy (anonymous):

m thinki9ng its c or d

OpenStudy (anonymous):

is the discriminant equal to or less than 0?

OpenStudy (anonymous):

less

OpenStudy (anonymous):

are you sure?

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

chrck again

OpenStudy (anonymous):

equal

OpenStudy (anonymous):

so, what does that mean?

OpenStudy (anonymous):

A

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

its A

OpenStudy (anonymous):

why is it A?

OpenStudy (anonymous):

its A isnt it?

OpenStudy (anonymous):

a quadratic cannot have 3 solutions

OpenStudy (anonymous):

well the only thing im left with is B

OpenStudy (anonymous):

why b? try reading what i initially wrote at the top

OpenStudy (anonymous):

Im going with C

OpenStudy (anonymous):

explain

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