Calculate the discriminant and use it to determine how many real-number roots the equation has.
3x^2 – 6x + 3 = 0
A. three real-number roots
B. two real-number roots
C. one real-number root
D. no real-number roots
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OpenStudy (anonymous):
\[\Delta=b^2-4ac\]
\[a=3\] \[b=-6\] \[c=3\]
OpenStudy (anonymous):
if the discriminant is less than 0, there are no real solutions
if the discriminant is equal to 0, there is one real solution
if the discriminant is larger than 0, there are 2 real solutions
OpenStudy (anonymous):
wich one is it
OpenStudy (anonymous):
try working it out for yourself
OpenStudy (anonymous):
m thinki9ng its c or d
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OpenStudy (anonymous):
is the discriminant equal to or less than 0?
OpenStudy (anonymous):
less
OpenStudy (anonymous):
are you sure?
OpenStudy (anonymous):
yes?
OpenStudy (anonymous):
chrck again
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OpenStudy (anonymous):
equal
OpenStudy (anonymous):
so, what does that mean?
OpenStudy (anonymous):
A
OpenStudy (anonymous):
what?
OpenStudy (anonymous):
its A
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OpenStudy (anonymous):
why is it A?
OpenStudy (anonymous):
its A isnt it?
OpenStudy (anonymous):
a quadratic cannot have 3 solutions
OpenStudy (anonymous):
well the only thing im left with is B
OpenStudy (anonymous):
why b? try reading what i initially wrote at the top
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