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Mathematics 15 Online
OpenStudy (anonymous):

5y + 2 =32

OpenStudy (anonymous):

Just isolate the variable and divide by 5.

OpenStudy (anonymous):

What does isolate mean?

OpenStudy (anonymous):

Make it so that the 5y is alone on one side first, then get rid of the 5 of by dividing everything by 5.

OpenStudy (anonymous):

2 + -2 + 5y = 32 + -2 2 + -2 = 0 0 + 5y = 32 + -2 5y = 32 +32 + -2 = 30 5y = 30 -2 Divide each side by '5'. y = 6

OpenStudy (anonymous):

Well I was hoping to let him do it, but I guess that's fine.

OpenStudy (anonymous):

Nope I don't get it sorry:l thanks

OpenStudy (anonymous):

Okay let's start from the beginning. This is an equation, meaning both sides are equal.

OpenStudy (anonymous):

We want to find what y is, so to do that we need to get it alone on one side by doing whatever is necessary. But remember that what you do to one side you must do to the other.

OpenStudy (anonymous):

So what is on the side with 5y in the original problem?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

Yep, so what could you do to get rid of that 2?

OpenStudy (anonymous):

I don't know:(

OpenStudy (anonymous):

You could subtract 2 from both sides right? That wouldn't technically change the fact that the equation is still accurate, but it would get rid of the 2.

OpenStudy (anonymous):

It's like having: 30=30 And subtracting 2 from both sides 28=28 The equation is still true

OpenStudy (anonymous):

Does that make sense?

OpenStudy (anonymous):

That would be 5y subtract 2 is 3

OpenStudy (anonymous):

2 - 2 = 0

OpenStudy (anonymous):

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