Question

can someone help me and show work for this question 2x^4(4x^2 + 3x + 1)

Answer 1

just multiply

Answer 2

2x^4 (4x^2) = 8x^6

Answer 3

thats what i am having trouble with because I am not sure how to multiply the coefficient and the exponents

Answer 4

then
2x^4 (3x) = 6x^5

Answer 5

then
2x^4(1) = 2x^4

Answer 6

Therefore you have
8x^6+6x^5+2x^4

Answer 7

To multiply exponents you add
a^x (a^b) = a^(x+b)

Answer 8

wow can you help me with a few more please?

Answer 9

sure

Answer 10

how about this one
(4x – 3)(2x^2 – 7x + 1)

Answer 11

@ivettef365

Answer 12

Distributive property

Answer 13

That is a long problem, first multiply (4x-3) (2x^2)
then by (-7x) then by (1)

Answer 14

still not sure how to multiply (4x-3) (2x^2)

Answer 15

2x4=8 / (x)(x) = x^2
then -3(2) = -6 / and x^2 stays the same, therefore
so you have 8x^2-6x^2

Answer 16

Do the same process and add all like terms

Answer 17

(4x-3)(-7x)
you have 4 x 7 - 28 / (x)(x) = x^2
(-3)(-7x) = 21x
therefore here you have
28x^2+21x

Answer 18

You have then (4x-3) (1) = 4x -3
now add everything

Answer 19

so it would be 30x^2 + 21x??

Answer 20

@ivettef365

Answer 21

@ikarus1991