Write an equation that is parallel to 2x-3y=4 and crosses the point (-2,-4)?
IMPORTANT LINE RELATED EQUATIONS TO KNOW AND MEMORIZE slope formula m= slope/ gradiant -- same thing \[m=\frac{y_2-y_1}{x_2-x_1}\] standard formula \[Ax+By=C\] point-slope formula \[y-y_1=m(x-x_1)\] slope-intercept formula b= y-intercept -- in the form of (0,y) \[y=mx+b\]
parallel line means that they share the same slope
i know there's a formula for this type of problem but i don't remember it..
you've been given all you need.
is it the point slope formula he posted?
yes
use slope intercept to determine the slope of the line
then use point slope in order to determine the equation of the parallel line that passes through the point
okay! i can do that.:) thank you
alternative : the equation of straight line which parallel to line ax+by=c and crosses the point (x1,y1) is ax + by = a(x1) + b(y1) so, it is 2x - 3y = 2(-2) - 3(-4) simplied, becomes 2x - 3y = 8
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