Question

Write an equation that is perpendicular to y=(3/2)x+2 and crosses the point (2,5)?
I tried this one myself but got the wrong answer. :/

Answer 1

With the point slop formula i got.. y=(3/2)x+2 and that can't be right.

Answer 2

*slope haha

Answer 3

The product of the slopes of two perpendicular lines must be -1
So, in the ecuation y=(3/2)x+2, the slope us 3/2.

So, let m be the slope of the requested perpendicular line, then
(3/2)*m = -1

Then you solve for m, and plugin in to the point slope formula.

Answer 4

so the slope for the other one has to be the opposite inverse, i think. it'd be 2/3?

Answer 5

negative 2/3, oops

Answer 6

Correct the slope is -2/3, then you can plug the numbers in the slope point ecuation
y-y_1 = m(x-x1)

Where (x1,y1) is the point adn m the slope.

Answer 7

thank you :)

Answer 8

Welcome