Question

Help please

√x - 2 + 5 = 6

Answer 1

x=3

Answer 2

again

please use parenthesis to clarify the part of the equation the square root encompasses

Answer 3

I DONT KNOW HOW

Answer 4

is x-2 inside the sqrt?

Answer 5

yes

Answer 6

this is what i meant

√(x - 2) + 5 = 6

Answer 7

what are the steps to solving

Answer 8

the goal is to solve for x

this means isolate x so its alone on one side

this can be done by adding/ subtracting/ multiplying/ dividing /etc things to BOTH sides


now the first step
√(x - 2) + 5 = 6

we want to move the 5 on the left side over to the right side

this can be done if we subtract 5 to both sides of the equation

what happens is on the left side, 5-5 =0 so it cancels out on the left side
on the right side, we get 6-5

√(x - 2) + 5-5 = 6-5
√(x - 2) = 1

Answer 9

the next step would be to get rid of that square root

any ideas?

Answer 10

subtract

Answer 11

actually, you want to square both sides

take both sides to the 2nd power

Answer 12

i did the rest:)

Answer 13

\[(\sqrt{x} )^2 = x\]

Answer 14

anyways once you square it

you get x-2 =1

then you add 2 to both sides
which cancels out the -2 on the right side to get

x=3