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Mathematics 21 Online
OpenStudy (anonymous):

√20x * √3x^3

OpenStudy (anonymous):

any answers for this one?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

|dw:1368843714251:dw|

OpenStudy (anonymous):

you got part backwards

OpenStudy (anonymous):

6x^2 square root 3

OpenStudy (anonymous):

\[\sqrt{60}=\sqrt{4\times 15}=2\sqrt{15}\] so a \(2\) comes out and a \(15\) stays in

OpenStudy (anonymous):

the \(x^2\) part is right, because \(\sqrt{x^4}=x^2\)

OpenStudy (anonymous):

18x

OpenStudy (anonymous):

final answer should be \[2x^2\sqrt{15}\]

OpenStudy (anonymous):

not an option

OpenStudy (anonymous):

really? is the question \[\sqrt{20x}\times \sqrt{3x^3}\]?

OpenStudy (jhannybean):

\[\sqrt{20x}*\sqrt{3x^3}\]\[\sqrt{60x^4}\]\[2x^2\sqrt{15}\]

OpenStudy (anonymous):

30*

OpenStudy (anonymous):

because if so i am sticking with the answer of \(2x^2\sqrt{15}\)

OpenStudy (anonymous):

ahhhh

OpenStudy (anonymous):

my sincerest apologies..... :(

OpenStudy (jhannybean):

I thought you multiplied...

OpenStudy (anonymous):

\[\sqrt{30x}\sqrt{3x^2}\] right?

OpenStudy (anonymous):

let me scroll up to see your answer again

OpenStudy (anonymous):

|dw:1368844042803:dw|

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