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12 sqrt(2) sqrt(x^3) sqrt(x^4)
remember that square root you can factor one ONE term per pair. so you have \(\sqrt{6x^3} = \sqrt{6 x^2 \times x}\) you have a pair so u can factor one of them out.
ok:)
same with the other side \(\sqrt{18x^4} = \sqrt{9 \times 2 \times x^2 \times x^2}\) so factor out the pair of 3's and the 2 x's from that.
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\(3x^2\sqrt{2}\)
thats not the answer
I know that's not the answer! I'm telling you how to get the answer so you know what you're doing.
oh
dont b mad:((
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