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OpenStudy (anonymous):

i need help with pre cal

OpenStudy (anonymous):

I'm in precal too -.-. It's tough. What's the question?

OpenStudy (anonymous):

G(x) = 3x 2 - 2x - 1 G(6) = 287 95 23 @Aki-chan

OpenStudy (anonymous):

i maen 3x^2

OpenStudy (anonymous):

ok the G(6) means you substitute ^ in for the x values of the function

OpenStudy (anonymous):

*6

OpenStudy (anonymous):

95

OpenStudy (anonymous):

Because of order of operations, you should get 108-12-1, giving you the answer 95

OpenStudy (anonymous):

yup lol

OpenStudy (anonymous):

F(x) = x 2 + 2 F(x 2) = @Aki-chan this one is a little confusing

OpenStudy (anonymous):

by x 2, is it x^2?

OpenStudy (anonymous):

yes @Aki-chan

OpenStudy (anonymous):

k

OpenStudy (anonymous):

basically, you do the same thing as before, substituting the x values for x^2

OpenStudy (anonymous):

3

OpenStudy (anonymous):

that should give you x^4+2x^2

OpenStudy (anonymous):

3?

OpenStudy (anonymous):

1

OpenStudy (anonymous):

What you substitute in depends on what the F(x) is

OpenStudy (anonymous):

I don't think the equation has an actual number answer

OpenStudy (anonymous):

Given: F(x) = x + 2 and G(x) = 3x + 5 (F - G) (x) =

OpenStudy (anonymous):

@Aki-chan

OpenStudy (anonymous):

? oh

OpenStudy (anonymous):

one sec...

OpenStudy (anonymous):

ok,so when it says (f-g), you literally subtract g from function f

OpenStudy (anonymous):

it would look like (f-g) = (x+2)-(3x+5). You distribute the negative/subtraction sign to both terms in (3x+5) Combining like terms, the answer would be -2x-3

OpenStudy (anonymous):

*If you're still stuck on how to do these function operations, this site can help: http://www.purplemath.com/modules/fcnops.htm

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