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There are 8 cars in a parking lot on a very cold day. Suppose the probability of any of them not starting is 0.13. What is the probability that exactly 2 of the cars will not start?
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ive never really been good at probability any help is great
The probability of one not starting is .13 The maximum probability is always 1. So what is the probability of any of them starting?
would it be .77 for them starting then?
.87
oh whoops sorry little out of it so its .87
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Sorry drawing a blank here . Ask @Mertsj he will be able to help
=1-probability that 6 will start
\[P(2\ won't\ start)=8C2\times (0.13)^{2}\times (0.87)^{6}=you\ can\ calculate\]
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