Question

when I factor y^3-4y the answer is y(y^2+2)(y-2) right

Answer 1

can you show how did u arrive at that

Answer 2

y(y^2+2)(y-2)
(y^2-2y+2y_4)
y(y^2-4)
=y^3-4y

Answer 3

y(y^2+2)(y-2)
y(y^2-2y+2y-4)
y(y^2-4)
=y^3-4y

Answer 4

ok can you tell me this :

\(y^2 \times y = ?\)

Answer 5

y^3

Answer 6

good :) , then how did you get the second step in your solution ?

Answer 7

worked whats in the () first the I combined like terms then i distributed the y that was on the out side of the () so did i work the problem right? is that the right factor

Answer 8

its not correct

Answer 9

you did a mistake at second step

Answer 10

you wrote y^2 x y as y^2, instead of y^3

Answer 11

check it once