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Mathematics 18 Online
OpenStudy (anonymous):

d^2y/dx^2 = 0, y'(0) = 2, y(0) = 0

OpenStudy (bahrom7893):

dy/dx = c where c is some constant

OpenStudy (bahrom7893):

y'(0) = 2, which means that dy/dx = 2

OpenStudy (bahrom7893):

y = Integral(2 dx) = 2x+C where C is another constant

OpenStudy (bahrom7893):

y(0) = 0 0=2*0+C

OpenStudy (bahrom7893):

C = 0, y=2x

OpenStudy (anonymous):

how is 2 c

OpenStudy (bahrom7893):

assuming your question was to find y. Next time it would be helpful to actually post the question.

OpenStudy (bahrom7893):

y'(0) = 2 y'(x) = C, there is no x, therefore C = 2

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