Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

solve ln2 + lnx = 5

jimthompson5910 (jim_thompson5910):

it's actually Ln not in

OpenStudy (anonymous):

oh oops

jimthompson5910 (jim_thompson5910):

Ln(2) + Ln(x) = 5 Ln(2x) = 5 .. use the rule that Ln(x) + Ln(y) = Ln(xy) 2x = e^5 ... convert to exponential form x = (1/2)*e^5 multiply both sides by 1/2 to isolate x

OpenStudy (nurali):

use the logarithmic laws - when you add logs you just multiply whatever is inside - ln 2 + ln x = ln (2*x). so ln(2x) = 5 raise both sides to the power of e e^(ln(2x)) = e^5 this thing above = 2x since e power and ln cancel out so 2x = e^5 x = (e^5) /2

OpenStudy (anonymous):

thanks!!!

jimthompson5910 (jim_thompson5910):

np

OpenStudy (anonymous):

so what do i put as a final answer

OpenStudy (nurali):

2x = e^5 2x = 148.41 x=148.41/2 x = 74.205

OpenStudy (anonymous):

thanks :)

OpenStudy (nurali):

Anytime.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!