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solve ln2 + lnx = 5
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it's actually Ln not in
oh oops
Ln(2) + Ln(x) = 5 Ln(2x) = 5 .. use the rule that Ln(x) + Ln(y) = Ln(xy) 2x = e^5 ... convert to exponential form x = (1/2)*e^5 multiply both sides by 1/2 to isolate x
use the logarithmic laws - when you add logs you just multiply whatever is inside - ln 2 + ln x = ln (2*x). so ln(2x) = 5 raise both sides to the power of e e^(ln(2x)) = e^5 this thing above = 2x since e power and ln cancel out so 2x = e^5 x = (e^5) /2
thanks!!!
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np
so what do i put as a final answer
2x = e^5 2x = 148.41 x=148.41/2 x = 74.205
thanks :)
Anytime.
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