3x^2+2x-1=0 is it imaginary irrational equal rational
use the discriminant formula D = b^2 - 4ac to figure out how many and what type of solutions there are
i do not kn ow that formula
3x^2+2x-1 is in the form ax^2+bx+c
in this case a = 3 b = 2 c = -1
plug all that into D = b^2 - 4ac and tell me what you get
17
D = b^2 - 4ac D = (2)^2 - 4(3)(-1) D = 4 + 12 D =16
D=17
since this is a) positive and b) a perfect square this means that you have 2 different rational solutions
how are you getting 17
disc=2^2-4*3*-1=16=4^2, which is positive and a perfect square Hence it is real and rational .
roots are equal only when D=0
i got 17 because i put the problem in right. you used two i used three for a.
no I used a = 3, not a = 2
I used b = 2, you must be mixing those up
my bad i wrote the formula wrong hahaha ok i got 16 now.
D>0 and a perfect square hence roots are real,rational and different.
|dw:1368913206171:dw| can you tell me how to work this i have no idea where to start
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