Question

d^2y/dx^2 = 0 , y'(0) = 4, y(0) = 1

Answer 1

What are you attempting to find?

Answer 2

y=2x

Answer 3

constant of the second question

Answer 4

Actually no this time y is not 2x

Answer 5

I know you get c for the first time

Answer 6

dy/dx = 4

Answer 7

then what is the integral of c

Answer 8

y = 4x+c, and since y(0) = 1:
1 = 4*0+c

Answer 9

So C=1
and y = 4x+1