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Can someone teach me how to verify that this equation is an identity step by step? cosA - sinA = (cos2A)/(cosA + sinA)
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that's easy, use the identity : cos2A = cos^2 A - sin^2 A
see your right side becomes, (cos2A)/(cosA + sinA) = (cos^2 A - sin^2 A)/(cosA + sinA)
then factor out the numerator by using the difference square formula : a^2 - b^2 = (a+b)(a-b)
ohhhh
i get it, thank you :)
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so, it can be = (cos A - sinA)(cos A + sinA)/(cosA + sinA) cancel out the similar term ;)
you're welcome
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