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Mathematics 11 Online
OpenStudy (anonymous):

What is the axis of symmetry for the graph of y=2x^2-6x+2 ? x=___

OpenStudy (mertsj):

The axis of symmetry is the vertical line through the vertex. So use x = -b/2a and find the x coordinate of the vertex.

OpenStudy (anonymous):

what is b and a?

OpenStudy (jhannybean):

your equation relates to the quadratic formula: \[y=ax^2+bx+c\] and your equation is \[y=2x^2-6x+2\] once you use your "b" and "a" from this equation to find \[x=\frac{ -b }{ 2a }\] which is the x-coordinate of the point on the vertex, you will use that x-value in your original equation to find the y-coordinate. then you will have found your (x,y) point that is your vertex point.

OpenStudy (jhannybean):

quadratic equation*

OpenStudy (anonymous):

so then it would be 6 over 2(2)?

OpenStudy (jhannybean):

Yes. \[x=\frac{ -(-6) }{ 2(2) }\]

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