Question

(sinA+cosAtanB)/(cosA-sinAtanB)=tan(a+b)

Answer 1

Multiply with cos B on numerator and denominator.

Answer 2

explain?

Answer 3

you will se that you get something similar to previous question

Answer 4

(sinA+cosAtanB) X cos B
________________________
(cosA-sinAtanB) X cos B

Answer 5

Try opening up the brackets .

Answer 6

ok, so you get this:
\[(sinAcosB+cosAcosBtanB)/(cosAcosB-sinAcosBtanB)\]
so what next?

Answer 7

tan B X cos B = ?

Answer 8

?

Answer 9

\[\tan B \times \cos B= .....\]

Can you find that ?

Answer 10

@hothand621 ?

Answer 11

ummmm no, i suck at harder trig

Answer 12

Hint: tan B = sinB / cosB

Answer 13

^^

Answer 14

yes
and that doesnt equal tan(a+b)

Answer 15

it equals sinB

Answer 16

Simplify it first :)
No need to be hurry :)

Answer 17

yep replace it in your question

Answer 18

replace what though

Answer 19

(sinA+cosAtanB) X cos B = sin A cos B+cos A sin B !

Answer 20

Seen that somewhere?

Answer 21

yes

Answer 22

Can you do it now ?

Answer 23

ummm give me a minute

Answer 24

i think so

Answer 25

what happens to the denominator?

Answer 26

Open up the brackets !

Answer 27

(cosA-sinAtanB) X cos B=.........

Answer 28

thanks man, solved :)

Answer 29

Great ! yw :)