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tan(45+a)+tan(45-a)=(2)/(cos2a)
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Open up tan(45+1) and tan (45-a)
*45+a
im up to (1+tanA)/(1-tanA) + (1-tanA)/(1+tanA)
\[\tan(x + y) = \frac{\tan(x) + \tan(y)}{1 - \tan(x)\tan(y)}\] \[\tan(x) - \tan(y) = \frac{\tan(x) - \tan(y)}{1 + \tan(x)\tan(y)}\]
*tan(x-y) on LHS..
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so whats next?
Take LCM first and combine the two terms by making their denominator equal..
ok
\[\frac{1 +\tan(a)}{1 - \tan(a)} + \frac{1 - \tan(a)}{1 + \tan(a)}\]
yeah next step please
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\[\implies \frac{(1 + \tan(a))^2 + (1 - \tan(a))^2 }{(1 - \tan(a))(1 + \tan(a))}\]
yes and after that?
Just expand the squares and cancel out what is being cancelled..
ok
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