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Factor the polynomial 8x^4+6x^3-2x^2 @dmezzullo @Destinymasha @waterineyes @SnuggieLad @So1D @smokeydabear @sar12 @primeralph @@erikgomez @Zale101 @Zarkon
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Nice way of tagging all in the question itself.. :)
1. Firstly you can factor out \(x^2\) out of it..
\[\implies \color{green}{x^2(8x^2 + 6x - 2)}\] Now you have got Quadratic equation, can you factor this equation or not?
2x^2(x+1)(4x-1)
Then I would bring out the 2 from waterineyes's equation.
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Yes you can..!!
yeah, yeah.........since ya'll got it, can I troll?
Go for it, the floor is yours
8x^4+6x^3-2x^2 =2x^2(4x^2+3x-1) =2x^2[4x^2+4x-1x-1] (4*-1=-4,4-1=3) now you can factorise
Someone has factorized it earlier, so no need to again factorize it.. :)
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