Question

how can i find for x to the nearest tenth

Answer 1

Use the pythagorean theorem. (\[a^2 + b^2 = c^2\])
The right triangle has one leg 8, and the hypotenuse, 9.
\[8^2 + b^2 = 9^2\]
Simplify:
64 + \[b^2\] = 81
-64 -64
------------------
\[b^2= 17\]
\[\sqrt{b^2} = \sqrt{17}\]
The side of one length is 4.1

Now we can solve the other triangle.

\[4.1^2 + b^2 = 6^2\]

\[16.8 + b^2 = 36\]

\[b^2= 19.2\]

\[\sqrt{b^2} = \sqrt{36}\]


X= 6

Answer 2

Not sure if I did it right, too much work.