how can i find for x to the nearest tenth

Question

anonymous · Answer

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goldphenoix · Answer

Use the pythagorean theorem. ($$a^2 + b^2 = c^2$$)
The right triangle has one leg 8, and the hypotenuse, 9. 
$$8^2 + b^2 = 9^2$$
Simplify:
 64 + $$b^2$$ = 81
-64             -64
------------------
      $$b^2= 17$$
       $$\sqrt{b^2} = \sqrt{17}$$
        The side of one length is 4.1

Now we can solve the other triangle. 

$$4.1^2 + b^2 = 6^2$$
 
  $$16.8 + b^2 = 36$$
 
     $$b^2= 19.2$$
      
       $$\sqrt{b^2} = \sqrt{36}$$
         

        X= 6

goldphenoix · Answer

Not sure if I did it right, too much work.