There are three red marbles, four white marbles, five yellow marbles, and six black marbles in a bag.

What is the probability of drawing two red marbles, if you don't replace the marble after you draw the first one?
A.) 1/51
B.) 1/6
C.) 1/36
D.) 1/54

Question

There are three red marbles, four white marbles, five yellow marbles, and six black marbles in a bag.

What is the probability of drawing two red marbles, if you don't replace the marble after you draw the first one? 
A.) 1/51
B.) 1/6
C.) 1/36
D.) 1/54

texaschic101 · Answer

total marbles : 3 + 4 + 5 + 6 = 18
red marble on first try = 3/18 = 1/6
red marble on second try = 2/17
now multiply......2/17 x 1/6 = 2/102 = 1/51
you might want to get a second opinion on this....just to be sure. Probability's are not my best subject.

anonymous · Answer

Good enough! Thanks!

texaschic101 · Answer

I hope it is correct :/

anonymous · Answer

It seems like it will be. I mean like the work seems to be correct