Question

ratios of right triangles helP!!

Answer 1

Know your SOH CAH TOA?

Answer 2

guess not :S

Answer 3

no :(

Answer 4

@Minaj check your textbook or your cheatsheet for the trig identities :|

Answer 5

http://www.mathsteacher.com.au/year10/ch15_trigonometry/01_ratios/Image3125.gif

Answer 6

SOH CAH TOA, a mnemonic pronounced Soh Kah Toah (or something like that) which stands for:
\[S=\frac{O}{H},~C=\frac{A}{H},~H=\frac{O}{A}\\
\sin\theta=\frac{\text{Opposite}}{\text{Hypotenuse}},~\cos\theta=\frac{\text{Adjacent}}{\text{Hypotenuse}},~\tan\theta=\frac{\text{Opposite}}{\text{Adjacent}}\]Once you know those basic ratios, this will be easy.

Answer 7

so what would be the ratio?

Answer 8

And that was supposed to be \(T=\frac{O}{A}\) above. Oops!

Answer 9

So you have theta in a corner and they are asking for what?

Answer 10

idk im so lost :(

Answer 11

Well, on the question part. What is it asking for?