Question

Please Help! Solve for d:
c(ad) + x = bd + ad(yz)

Answer 1

Hey brankdondowell1! Welcome to OpenStudy!

To start this equation, \[c(ad) + x = bd + ad(yz)\] I suggest you would do the distibution method to get rid of any of the parenthesis.

Answer 2

I'm not sure I know how to do that.

Answer 3

Sorry, had to step away.

To do the distrabution method, its quite simple. Lets use your equation: \[c(ad) + x = bd + ad(yz)\] The first thign you would do is that the \[c\] and multiply it my the ad, and you would have \[cad+x=bd+ad(yz)\] next, you would multiply the \[ad\] and multiply it by the yz, like so: \[cad+x=bd+adyz\] I don't see much more that you can really do with this, becasue there's no numbers or anything like that.