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Mathematics 13 Online
OpenStudy (anonymous):

Please Help! Solve for d: c(ad) + x = bd + ad(yz)

OpenStudy (andriod09):

Hey brankdondowell1! Welcome to OpenStudy! To start this equation, \[c(ad) + x = bd + ad(yz)\] I suggest you would do the distibution method to get rid of any of the parenthesis.

OpenStudy (anonymous):

I'm not sure I know how to do that.

OpenStudy (andriod09):

Sorry, had to step away. To do the distrabution method, its quite simple. Lets use your equation: \[c(ad) + x = bd + ad(yz)\] The first thign you would do is that the \[c\] and multiply it my the ad, and you would have \[cad+x=bd+ad(yz)\] next, you would multiply the \[ad\] and multiply it by the yz, like so: \[cad+x=bd+adyz\] I don't see much more that you can really do with this, becasue there's no numbers or anything like that.

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