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Find the equation of a parabola with the vertex at (-3,-2) and directrix of X = 1
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(y+2)^2= 4(x+3)^2
I think so
|dw:1369414937672:dw|
y = (x+3)^2 - 2
@Euler271 can you explain me how to get that equation?
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you were thinking the equation of a circle. y = a(x-h)^2 + k is the general equation of a parabola, where the point (h, k) is the vertex and a is the directrix.
nope, y ^2 = 4px with directrix x = 1( or p = 1) is it not from conic section?
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