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Does this converges or diverges? integral 1 to infinity x^-1/3 dx
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I got \[\frac{ 3 }{ 2 } \lim_{b \to infinity} (b ^{2/3} - 1^{2/3})\]
which = infinity. therefore it diverges
okay
\[\int\limits_{1}^{t}x ^{\frac{ -1 }{ 3 }}dx=\[\lim_{t \rightarrow \infty}\int\limits_{1}^{t} x ^{\frac{ -1 }{ 3 }}dx= \lim_{t \rightarrow \infty}\left[ \frac{ x ^{\frac{ 2 }{3 }} }{\frac{ 2 }{ 3 } } \right]_{1 }^{t} \[=\frac{ 3 }{ 2 }\lim_{t \rightarrow \infty} \left( \left( t \right)^{\frac{ 2 }{ 3 }}-1 \right)\rightarrow \infty \] \] therefore it diverges.
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