Question

Can someone change this into logarithmic form?
f(x) = 8.04e^(0.07x)

Answer 1

$$
f(x)=8.04e^{0.07x}\\
\text{get ln() on both}\\
ln(f(x)))=\bf ln(8.04e^{\color{red}{0.07x}})\\
ln(8.04e^{\color{red}{0.07x}}) \implies ln(8.04)+ln(e^{\color{red}{0.07x}})\\
\text{by the cancellation rules } log_aa^x = x\\
ln(8.04)+\color{red}{0.07x}\\
$$

is that what's expected?

Answer 2

I think so! Thanks (: