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OpenStudy (anonymous):
OpenStudy (anonymous):
dont know how to use a graphing calc
OpenStudy (anonymous):
one way to look at this is letting x = rate of first mechanic and y = rate of second mechanic.
rate = price/hour --> price = hour * rate
15x + 5y = 1200
x + y = 130
OpenStudy (anonymous):
so now what?
OpenStudy (compassionate):
You want to solve using the elimination method
15x + 5y = 1200
x + y = 130
You want to multiply the bottom equation by either negative five to cancel y or negative 15 to cancel x.
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OpenStudy (anonymous):
so 1200=15+5*y?
OpenStudy (anonymous):
you use substitution; easier to start with the second line and re-arranging it to : y = 130 - x.
this is plugged in the first: 15x + 5(130 - x) = 1200
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
so 10x+650=1200?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
and then its 55?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
but thats whose rate?
OpenStudy (anonymous):
the first guy, who worked 15 hours
OpenStudy (anonymous):
okay so how do i get the second? by plugging in the 15 in the y?
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OpenStudy (anonymous):
by using x + y = 130
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
so 55+5=130?
OpenStudy (anonymous):
wait that is not right lol
OpenStudy (anonymous):
so x=55 right?
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OpenStudy (anonymous):
yes x = 55
OpenStudy (anonymous):
okay so 55+y=130 right?
OpenStudy (anonymous):
y=75?
OpenStudy (anonymous):
so X=55
Y=75
OpenStudy (anonymous):
yes
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