first find the cost per square inch of each tile
the total area available is 24ft^2. And the minimum area of the mosaic should be 15 ft^2. So the 15 <= Area <= 24
Lot of questions in my mind maybe I am over thinking it.
consider a few things: cost per area of the 4"x4" is 3.50/16 sq in cost per area of the 6"x12" tile is 4.50/72 sq in <--- much cheaper to keep things cheap, tile the smallest amount possible at least 3 feet tall and 5 feet wide or 36" x 60" notice the large tile fits evenly into that space so use only large tiles
Ok he wants the letters to be horizontal. So if he uses the 4 x 4 tile how many can he arrange in 5ft to 6 ft. 5ft is 60 inches. so he can put 15 of them. 6 ft is 72 inches. so he needs 18 of them. the height is 3ft to 4 ft. 3ft is 36 inches. so he needs 9 of them 4 ft is 48 inches. so needs 12 of them. So the mosaic using only the smaller tiles will be 9 x 15 = 135 tiles minimum or 18 x 12 = 216 tiles The cost of that will be 135 x 3.5 to 216 x 3.5 = 472. 5 to 756 dollars
Now if he uses large tiles 6 x 12 5 ft= 60 inches he needs , he needs 5 of them 6 ft = 72 inches , he needs 6 of them 3 ft = 36 inches , he needs 6 of them, 4 ft = 48 inches , he needs 8 of them so using the large tiles he needs 6 x 5 = 30 tiles or 6 x 8 = 48 tiles. Now each tile costs 4.5 so he will spend minimum 30 x 4.5 = 135 or 48 x 4.5 = 216 Either way he should go for the 3 x 5 mosaic all with large tiles. he needs 30 tiles of the larger one
I think wants the words to all be horizontal in the final mosaic. means the 6x12 must be used oriented with 12 inches being the horizontal (12 is the width)
yes that is what I did in my calculations
even then they go evenly
This is a strange question...
the horizontal orientation given only to calculate the no. of tiles finally
even then the area works to be the same. hmm.. if I flip the orientation and take 12 ft vertically I need 3 of the tiles. and put 6 ft horizontally , I need 10 of those. So the arrangement will be 3 x 10 which is still 30 tiles.