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tan(sin^-1(-1))=?
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first start from sin^-1(-1)
do you know what is it ?
no
i dont remember how to solve for inverse functions
well just think of a value between -pi/2 and pi/2 for sine function that gives -1
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honestly , i am so confuse. i havent done these since first semester
use a unit circle http://en.wikipedia.org/wiki/File:Unit_circle_angles_color.svg cos is horizontal component sine is vertical component tan is ratio sin/cos First find the angle such that sin(angle) = -1 then compute tan(angle)
answer is -1/0 which approaches -infinity
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