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3x+1/3<=3x+2/3
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Is it \[\frac{3x+1}{3} \leq \frac{3x+2}{3}\]
Uhh i don't know i don't get this at all so i'm just asking if someone could help me get the answer
No I meant is your question \[\frac{3x+1}{3} \leq \frac{3x+2}{3}???\]
Or \[3x+\frac{1}{3} \leq 3x+\frac{2}{3}\]
It's confusing the way you've written 3x+1/3<=3x+2/3
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oh that's the way my teacher wrote it so i don't know
The first one or the second one?
If it's \[\frac{3x+1}{3} \leq \frac{3x+2}{3}\] Then it's 'true'. \(\frac{3x+2}{3}\) is larger than \(\frac{3x+1}{3}\)
it's the 2nd one
\[3x+\frac{1}{3} \leq 3x+\frac{2}{3}\] True as well, the difference is \(-\frac{1}{3}\)
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