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Mathematics 13 Online
OpenStudy (anonymous):

3x+1/3<=3x+2/3

sam (.sam.):

Is it \[\frac{3x+1}{3} \leq \frac{3x+2}{3}\]

OpenStudy (anonymous):

Uhh i don't know i don't get this at all so i'm just asking if someone could help me get the answer

sam (.sam.):

No I meant is your question \[\frac{3x+1}{3} \leq \frac{3x+2}{3}???\]

sam (.sam.):

Or \[3x+\frac{1}{3} \leq 3x+\frac{2}{3}\]

sam (.sam.):

It's confusing the way you've written 3x+1/3<=3x+2/3

OpenStudy (anonymous):

oh that's the way my teacher wrote it so i don't know

sam (.sam.):

The first one or the second one?

sam (.sam.):

If it's \[\frac{3x+1}{3} \leq \frac{3x+2}{3}\] Then it's 'true'. \(\frac{3x+2}{3}\) is larger than \(\frac{3x+1}{3}\)

OpenStudy (anonymous):

it's the 2nd one

sam (.sam.):

\[3x+\frac{1}{3} \leq 3x+\frac{2}{3}\] True as well, the difference is \(-\frac{1}{3}\)

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