Eliminate the parameter.
x = t - 3, y = t^2 + 5

Question

Eliminate the parameter. 
x = t - 3, y = t^2 + 5

rajee_sam · Answer

from first eqn you have x = t-3 so t = x + 3

Now put that in the second

y = t^2 + 5 put t = x + 3

y = (x + 3)^2 + 5 = x^2 + 6x + 9 +5 = x^2 + 6x + 14

anonymous · Answer

ohh okay I forgot to square it after I substituted it. thank you could you help me with this one? Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°

anonymous · Answer

i got (5 square root 2, 315°), (-5 square root 2, 135°)

rajee_sam · Answer

I am not good at Polar coordinates

rajee_sam · Answer

Give me a few minutes I will try

rajee_sam · Answer

My computer is acting up

anonymous · Answer

no problem

rajee_sam · Answer

you have 5 root 2 that is correct.

But -5root2 is not.

They are asking for all polar coordinates for which magnitude is 5 root 2 and the angle for which tan theta = 1

rajee_sam · Answer

so your coordinates will be between 0 and 360°

$$( 5\sqrt{2}, 45°) ; (5\sqrt{2}, 135° ); (5\sqrt{2}, 225°) ; (5\sqrt{2}, 315°)$$

anonymous · Answer

which pair is it though?