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Omg, you're an Aleks student :o Do you go to Primavera as well? Anyways.. You're going to solve the quadratic equation by completing the square, so add 9 to both sides. \[x ^{2}-2x=9\] Take one half of the coefficient of x and square it, then add it to both sides. \[x ^{2}-2x+1=10\] factor the left hand side. \[\left( x-1 \right)^{2}=10\] Eliminate the exponent. \[x-1=\sqrt{10}\] or \[x-1=-\sqrt{10}\] Solve for x by adding 1 to each side. \[x=1+\sqrt{10}\] or \[x-1=-\sqrt{10}\] Solve for x, add one to both sides. \[x=1+\sqrt{10}\] or \[x=1-\sqrt{10}\] And that's your answer. c:
\[x=1-\sqrt{10}\] ↑ ↑ ↑ answer c:
How do I find the form?
thanks I got it
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