Question

Somebody, please help

The functions f(θ) and g(θ) are sine functions, where f(0) = g(0) = 0. The amplitude of f(θ) is twice the amplitude of g(θ). The period of f(θ) is one-half the period of g(θ). If g(θ) has a period of 2pi and f (pi/4) = 4, write the function rule for g(θ).

Answer 1

this is confusing, somebody tell me how to do it

Answer 2

2sin(o)

Answer 3

'o' is theta here.

Answer 4

given that period of "f" is pi and f(pi/4) = 4
also in the equation:
y = Asin(Bx) .... B = 2pi/period
for function "f" ... B = 2
--> 4 = Asin(2*pi/4)
--> 4 = Asin(pi/2)
--> 4 = A

amplitude of "g" is half of "f" .... therefore amplitude of "g" is 2
period is 2pi so B = 1

g(x) = 2sin(x)
same as @kutabs wrote

Answer 5

Oh, thanks A lot...Now i understand..it was just confusing

Answer 6

Gave ya a medal :D

Answer 7

No medal for me! Oh man! :(