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OpenStudy (luigi0210):
Well since both numbers have a minus we know it has to be a (x+a)(x-b)
OpenStudy (luigi0210):
In this case the negative number is greater
OpenStudy (cwrw238):
now you need to find 2 numbers whose product is -72
which when added give -6
OpenStudy (luigi0210):
What are all the factors of 72 first of all?
OpenStudy (zzr0ck3r):
(x-3)^2 = 72+9
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OpenStudy (zzr0ck3r):
yet another way^
OpenStudy (luigi0210):
Is that completing the square?
OpenStudy (cwrw238):
yes
OpenStudy (luigi0210):
@Indiadabest do you know how to finish it?
OpenStudy (anonymous):
no
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OpenStudy (luigi0210):
Come on now, we pretty much numbed it down for you
OpenStudy (zzr0ck3r):
x^2 - 6x-72 = x^2 -12x+6x-72
because -12*6 = -72 and -12+6 = -6
so now factor out a x from the pair of terms on the left and a 6 from the ones on the right
x(x-12)+6(x-12)
factor out the x-12
(x-12)(x+6)
OpenStudy (luigi0210):
It's what zz is showing.. I never actually learned that method
OpenStudy (zzr0ck3r):
or complete the square
x^2-6x-72 = 0
cut the middle term in half and then do this
(x-3)^2 = 0 + 72 + 9 = 81
(x-3)^2 = 81
(x-3) = -9 and x-3 = 9
x = -12 or x = 6
OpenStudy (zzr0ck3r):
the plus 9 on the rhs is making up for the 3 on the left squared
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OpenStudy (luigi0210):
And if you prefer you could graph it and see where it intersects the x-axis