Solve for x show your work: x² -6x -72
Well since both numbers have a minus we know it has to be a (x+a)(x-b)
In this case the negative number is greater
now you need to find 2 numbers whose product is -72 which when added give -6
What are all the factors of 72 first of all?
(x-3)^2 = 72+9
yet another way^
Is that completing the square?
yes
@Indiadabest do you know how to finish it?
no
Come on now, we pretty much numbed it down for you
x^2 - 6x-72 = x^2 -12x+6x-72 because -12*6 = -72 and -12+6 = -6 so now factor out a x from the pair of terms on the left and a 6 from the ones on the right x(x-12)+6(x-12) factor out the x-12 (x-12)(x+6)
It's what zz is showing.. I never actually learned that method
or complete the square x^2-6x-72 = 0 cut the middle term in half and then do this (x-3)^2 = 0 + 72 + 9 = 81 (x-3)^2 = 81 (x-3) = -9 and x-3 = 9 x = -12 or x = 6
the plus 9 on the rhs is making up for the 3 on the left squared
And if you prefer you could graph it and see where it intersects the x-axis
Join our real-time social learning platform and learn together with your friends!