jenn has $150 saved for lunch money. each day she takes out $2.50 for lunch write the equation for this function???D:
What we know so far is that the equation is linear, correct?
im sorry replace the word equation with formula the section im in is called arithmetic and geometric sequencing if that helps
we could still y=mx+b if I'm not mistaken
sounds about right
Okay, so far we know that we have two numbers. The total of 150 and 2.50, now we need to figure out which one gets the variable x
wouldnt 2.50 get the x?
Yes it would, and instead of it being y=mx+b it's gonna be y=b-mx because we are taking out money not adding some.
Let m = money Jenn has She starts with m = 150 before spending any money on lunches On day 1, she takes out $2.50, so she ends up with m = 150 - 2.50 On day 2, she starts with m = 150 - 2.50 = 147.50, and she spends another 2.50, so she ends up with m = 147.50 - 2.50, but this is also m = 150 - 2.50 - 2.50 or m = 150 - 2*2.50, She took out 2 times 2.50, one times 2.50 on day one and one times 2.50 on day 2. On day 3, she ends up with 150 - 2.50 - 2.50 - 2.50 or m = 150 - 3*2.50 Let d = number of the day On any day d, she will end up with m = 150 - d*2.50 after paying for lunch. The formula then is m = 150 - 2.5d Where m = the money she will have after paying for lunch on day d. Now that you have the formula, a question you can ask is how many days will it take for her to spend all her money. That means after spending 2.50 in the last day, she will have 0 dollars left. That is when m = 0. Solve 0 = 150 - 2.5d for d, to find out.
... Yea pretty much what mathstudent explained :l
Join our real-time social learning platform and learn together with your friends!