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cot (-pi/3)
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Have you considered an equivalent expression in terms of sine and cosine?
yes, I am having trouble solving it
Let's see your sine and cosine version.
cos= 2squarroot 3/3
I was hoping for this: \(\cot(-\pi/3) = \dfrac{\cos(-\pi/3)}{\sin(-\pi/3)}\)
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so is it the square root of 3/3
Simplest thing is to say that the cot is the reciprocal of the tangent. Tangent of pi/3=sqrt3. cotangent is 1/sqrt3=sqrt3/3
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