Question

help with sigma notation please

Answer 1

\[\sum_{i=1}^{7}4(3)(i-1)\]

Answer 2

@jim_thompson5910

Answer 3

Determine the geometric partial sum

Answer 4

this is a geometric series, but I don't see any exponents

Answer 5

is the "i-1" an exponent?

Answer 6

yes

Answer 7

ok you plug in i = 1, i = 2, i = 3, etc all the way up to i = 7

evaluate each expression, then add up the results

Answer 8

sound doable?

Answer 9

yes
4(3)^(1-1)+ 4(3)^(2-1)+ 4(3)^(3-1)+ 4(3)^(4-1)+ 4(3)^(5-1)+ 4(3)^(6-1)+ 4(3)^(7-1)
12^0 12^1 12^2 12^3 12^4 12^5 12^6
1+12+144+1728+20736+248832+2985984
3257437
thank you

Answer 10

hmm that answer is way too big

Answer 11

4(3)^(1-1)+ 4(3)^(2-1)+ 4(3)^(3-1)+ 4(3)^(4-1)+ 4(3)^(5-1)+ 4(3)^(6-1)+ 4(3)^(7-1)


4(3)^(0)+4(3)^(1)+4(3)^(2)+4(3)^(3)+4(3)^(4)+4(3)^(5)+4(3)^(6)


4(1)+4(3)+4(9)+4(27)+4(81)+4(243)+4(729) <--- you followed PEMDAS incorrectly on this step


4+12+36+108+324+972+2916


4372

Answer 12

darn it, we're dumb. thanks though

Answer 13

silly mistake, yw