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OpenStudy (anonymous):
What is the difference of r+2/r+4 - 3/r+1
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mathslover (mathslover):
Is it : \(\cfrac{r+2}{r+4} - \cfrac{3}{r+1} \) ?
OpenStudy (anonymous):
yes
mathslover (mathslover):
Do you know how to take LCM ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
@passive13
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mathslover (mathslover):
Moomoocow123, can you tell me what you tried yet?
OpenStudy (anonymous):
r^2-10/(r+4)(r+1) is one of the options?
OpenStudy (anonymous):
yup!
OpenStudy (anonymous):
is it correct?
OpenStudy (anonymous):
think so
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OpenStudy (anonymous):
@passive13, buddy we've gone over this...you cant give out an answer like that.
OpenStudy (jhannybean):
Multiply,
\[\frac{ \color{red}{(r+1)} }{ \color{red}{(r+1)} }*\frac{ (r+2) }{ (r+4) }-\frac{ \color{blue}{(r+4)} }{ \color{blue}{(r+4)} }*\frac{ 3 }{ (r+1) }\]
OpenStudy (anonymous):
i shall start charging people then lol
OpenStudy (jhannybean):
\[\frac{ (r+1)(r+2) }{ (r+1)(r+4) }-\frac{ 3(r+4) }{ (r+4)(r+1) }\]\[\frac{ r^2+2r+r+2 }{ (r+1)(r+4) }- \frac{ 3r+12 }{ (r+1)(r+4) }\] combine.\[\frac{ r^2+3r+2-3r-12 }{ (r+1)(r+4) }\]
OpenStudy (jhannybean):
Simplify and you've got your answer.
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