Question

PLEASE HELP !!!!!!!!!!!!!!!!!!

Answer 1

Completely off topic ^

Answer 2

for school

Answer 3

yes , yes i do

Answer 4

no

Answer 5

I know. But Harry Styles its just my friends call me boobear

Answer 6

no

Answer 7

Yes harry is my favorite

Answer 8

Okay bai

Answer 9

@amistre64

Answer 10

L.c.m of 3x+9 and x+3 is 3x+9.
3x+9=3(x+3)
When u multiply by 3x+9 both sides u will get
\[(3x+9)*\frac{1}{3x+9}-(3x+9)*\frac{2}{x+3}=2*(3x+9)\]
\[\cancel{(3x+9)}*\frac{1}{\cancel{3x+9}}-3\cancel{(x+3)}*\frac{2}{\cancel{x+3}}=2*(3x+9)\]
\[1-6=2*3x+2*9\]
\[1-6=6x+18\]
solve for x.
Does that help? @boobear7411

Answer 11

Nice explanation @ajprincess

Answer 12

i dont get it ?

Answer 13

what do u get when u factorise 3x+9 @boobear7411

Answer 14

-3 ??

Answer 15

nope:(

Answer 16

ugh

Answer 17

3(x+3)

Answer 18

?

Answer 19

yup

Answer 20

Alright so what do i do next ?

Answer 21

i'll be right back i have to do something

Answer 22

as u can see the denominators of the given fractions are different. if u want to add or subtract fractions with different denominators first u need to find a common denominator. this will be the lcm of the two denominators. in this case the common denominator is the lcm of 3x+9 and x+3. what is the lcm?

Answer 23

Icm ?

Answer 24

least common multiple

Answer 25

Oh i have no idea.

Answer 26

Really sorry. hav to go nw.

Answer 27

Omg . i s=need the answerrr

Answer 28

ok I will try to continue ..lemme go through the working above

Answer 29

Give me a minute

Answer 30

ok

Answer 31

Well to make things simpler we need to get rid of the fractions first

Answer 32

ok

Answer 33

Before doing so note that 3pi+9=3(pi+3)

Answer 34

ok

Answer 35

So as ajprincess pointed out we can make the denominators same by just multiplying 2nd term with 3

Answer 36

oops its x not pi lol

Answer 37

alright

Answer 38

Anyways

\[\dfrac{1}{3(x+3)}-\dfrac{3 \times 2}{3(x+3)}=2\]

Answer 39

Notice that denominators are same now

Answer 40

So simply subtract them

Answer 41

\[\dfrac{1-6}{3(x+3)}=2\]

Answer 42

what to do next

Answer 43

multiply with 3(x+3) on both sides

Answer 44

\[-5=6(x+3)\]

Answer 45

I hope you an do it from there :)

Answer 46

6?