Question

help @ganeshie8

Answer 1

@AravindG

Answer 2

write prime factorization for each of the given number

Answer 3

nvm i need help with this i figured that one out @ganeshie8

Answer 4

oh good :) what did u get as answer

Answer 5

100

Answer 6

perfect !

Answer 7

i dont understand the new one

Answer 8

\(28y^7x^3 \)

\(4y^3x^3 \)

Answer 9

prime factors of 28 = 4*7

Answer 10

\(4*7y^7x^3 \)

\(4y^3x^3 \)

Answer 11

4=2*2 right

Answer 12

yeah thats right ! lets see the greatest things

Answer 13

\(2^2*7*y^7x^3 \)

\(2^2*7*y^3x^3 \)

Answer 14

for 2 :-
2^2 is the largest

for 7 :-
7 is the largest

for y :-
y^7 is the largest

for x :-
x^3 is the largest

Answer 15

so LCM = 2^2*7*y^7x^3
= 4*7y^7x^3
= 28y^7x^3

Answer 16

does that make some sense

Answer 17

the lcm is 28y^7x^3?

Answer 18

yes !

Answer 19

thank you so much

Answer 20

np :)