need help for slope things look at the picture
and this one 2
For the first one,you have points (0,3) and (9,0) . you can use the formula for the slope we just talked about in our last problem \[m=\frac{ y_{2}-y_{1} }{ m_{2}-m_{1} }\] to find the slope.
1 over 3 negative i dont know im confused
-1/3 and 2/3 . You needed the answer only didn't you? The formula is (y2-y1)/(x2-x1) where the coordinates x1,y1 represent the point where the line cuts x-axis and x2,y2 where the line cuts y-axis
Are you taking an online test @msellier ? :/
The slope can be negative. Since slope= tan(theta) and tan(theta) can be negative, in certain domains. You'll learn it in Trigonometry.
no online question preparing me for test
oh ok
?? help still dont get it ???? :/
What didn't you get? I gave you the answer, like you asked.
oh sorry didn't that thanks dude
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