Question

Help me?

Answer 1

help someone?

Answer 2

right the left hand side in terms of sine and cosine, then add

Answer 3

right the left hand side in terms of sine and cosine and then at last Add .

Answer 4

\[\frac{b}{a}+\frac{a}{b}=\frac{a^2+b^2}{ab}\]
\[\frac{\sin(x)}{\cos(x)}+\frac{\cos(x)}{\sin(x)}\]
\[=\frac{\sin^2(x)+\cos^2(x)}{\sin(x)\times \cos(x)}\]

Answer 5

only one more step to get the answer, the only real trig step here
what is \(\sin^2(x)+\cos^2(x)\) ?

Answer 6

well 1 is not the answer. However the fraction becomes

\[\frac{ 1 }{ \sin \theta \cos \theta }\]

Answer 7

which is the required right hand side. :)

Answer 8

yes, that is what it is, and that is what you want

Answer 9

Yes.

Answer 10

you were supposed to show by algebra that the left hand side equals the right hand side
and that is what you need