Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

In ∆ABC, ∠C is a right angle, what is the measure of x?

OpenStudy (anonymous):

OpenStudy (e.mccormick):

How did you try solving it?

OpenStudy (anonymous):

cos(B) = Adjacent / Hypotenuse cos(B) = BC / AB cos(B) = 28.3/66.4

OpenStudy (anonymous):

Yeah so thats correct..you can refer to trigonometric tables also

OpenStudy (anonymous):

My answer choices are: 42.1 64.8 23.1 25.2

OpenStudy (e.mccormick):

Did you do an arccosine of that?

OpenStudy (anonymous):

I'm confused on how to finish solving it.

OpenStudy (e.mccormick):

\(\cos\theta=n\implies\theta= \cos^{-1}(n)\)

OpenStudy (johnweldon1993):

You would use COS when you KNOW the measure of the angle...you use COS^-1 when you NEED the measure of the angle...so instead of cos(B) = 28.3/66.4 do arcos(B) = 28.3/66.4

OpenStudy (johnweldon1993):

Sorry *edit* Arccos(28.3/66.4) = Angle

OpenStudy (e.mccormick):

\(\cos (B) = 28.3/66.4\implies \measuredangle B =\cos^{-1}(28.3/66.4)\)

OpenStudy (anonymous):

How do I solve that?

OpenStudy (e.mccormick):

On your calculator, is there an arccos function?

OpenStudy (anonymous):

I got 64.77 So my answer must be 64.8 :)

OpenStudy (e.mccormick):

Yep!

OpenStudy (anonymous):

Thank you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!