In ∆ABC, ∠C is a right angle, what is the measure of x?
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OpenStudy (anonymous):
OpenStudy (e.mccormick):
How did you try solving it?
OpenStudy (anonymous):
cos(B) = Adjacent / Hypotenuse
cos(B) = BC / AB
cos(B) = 28.3/66.4
OpenStudy (anonymous):
Yeah so thats correct..you can refer to trigonometric tables also
OpenStudy (anonymous):
My answer choices are:
42.1
64.8
23.1
25.2
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OpenStudy (e.mccormick):
Did you do an arccosine of that?
OpenStudy (anonymous):
I'm confused on how to finish solving it.
OpenStudy (e.mccormick):
\(\cos\theta=n\implies\theta= \cos^{-1}(n)\)
OpenStudy (johnweldon1993):
You would use COS when you KNOW the measure of the angle...you use COS^-1 when you NEED the measure of the angle...so
instead of cos(B) = 28.3/66.4
do
arcos(B) = 28.3/66.4
OpenStudy (johnweldon1993):
Sorry *edit* Arccos(28.3/66.4) = Angle
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OpenStudy (e.mccormick):
\(\cos (B) = 28.3/66.4\implies \measuredangle B =\cos^{-1}(28.3/66.4)\)
OpenStudy (anonymous):
How do I solve that?
OpenStudy (e.mccormick):
On your calculator, is there an arccos function?
OpenStudy (anonymous):
I got 64.77 So my answer must be 64.8 :)
OpenStudy (e.mccormick):
Yep!
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