In ∆ABC, ∠C is a right angle, what is the measure of x?
How did you try solving it?
cos(B) = Adjacent / Hypotenuse cos(B) = BC / AB cos(B) = 28.3/66.4
Yeah so thats correct..you can refer to trigonometric tables also
My answer choices are: 42.1 64.8 23.1 25.2
Did you do an arccosine of that?
I'm confused on how to finish solving it.
\(\cos\theta=n\implies\theta= \cos^{-1}(n)\)
You would use COS when you KNOW the measure of the angle...you use COS^-1 when you NEED the measure of the angle...so instead of cos(B) = 28.3/66.4 do arcos(B) = 28.3/66.4
Sorry *edit* Arccos(28.3/66.4) = Angle
\(\cos (B) = 28.3/66.4\implies \measuredangle B =\cos^{-1}(28.3/66.4)\)
How do I solve that?
On your calculator, is there an arccos function?
I got 64.77 So my answer must be 64.8 :)
Yep!
Thank you!
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