Solve the system of inequalities by graphing
\[4y < -3x \] \[y < \frac{ 3 }{ 4 }x\]
@AravindG
@Ashleyisakitty
Graph the equations first.. 4y=-3x and 4y=3x..
|dw:1369771775966:dw|
That's all I can do :(
|dw:1369771874733:dw| it would be something like this with slopes -3/4 and 3/4 respectively..
Ok so when it says solve it by graphing thats what I put, correct?
umm its not solved yet.. but thats what you do first.. graph the equalities.. i'll write the next step in the next post.
next.. you need to remember this.. whenever you have anything like y > x + something or whatever.. i mean a linear equation with y greater than x.. it means you have to gepah the area above the line.. and for a less than sign... y< x + something.. a linear equation. with y less than x .. it basically means the area below the line.. i'll mark the area in the figure in the next post.. you get this btw? http://www.purplemath.com/modules/ineqgrph.htm This can be helpful.. i dont really explain things all that well..
Cheers, for trying though :) you helped me out
|dw:1369772278538:dw| the lines marks the area for line 4y<-3x and the circles kinda thing marks the area for the line 4y<3x..
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