Question

Medal and fan awarded

which expressioon is the simplified form of sqrt 63w ^36
3w^6 sqrt 7
9w^6 sqrt 7
3w^18 sqrt 7
9w^18 sqrt 7

Answer 1

\[\large \sqrt{63}*\sqrt{w^{36}}\]

Answer 2

explain

Answer 3

\[\sqrt{63w^{36}}= \sqrt{63} * w^{36/2} = w^{18} * \sqrt{9 * 7} = 3w^{18} * \sqrt{7}\]

Answer 4

So you have \[\sqrt{63} = \sqrt{3*3*7} \] and \[w ^{36/2}= w^{18}\] combine. \[\large 3\sqrt{7}*w^{18}\]

Answer 5

Yeah what Eleven got.....lol

Answer 6

thank u !! I wish I could give u both a medal lol
could u guys help with another ?

Answer 7

ok

Answer 8

what is the exact value of the expression 2 sqrt7 + sqrt14 + 4 sqrt7 ?
4 sqrt7 + sqrt14
6 sqrt7 + sqrt 14
7 sqr28
sqrt28

Answer 9

\[2\sqrt{7}+\sqrt{14}+4\sqrt{7}\] just break down the square root. of sqrt 14. \[6\sqrt{7}+\sqrt{14}\]

Answer 10

remove tht middle line. lol. that wasnt needed.

Answer 11

ok thanks
what is the exact value of the expression sqrt486 - sqrt24 + sqrt6? simplify is possible
2 sqrt2
2 sqrt6
6 sqrt2
8 sqrt6

Answer 12

meant to say you CANT factor out anything from rad 14, so just leave it as it is.

Answer 13

Oh ok. I'm not too good with sqrt anything.

Answer 14

i typed it out wrong -_-

Answer 15

oh ok. I was wondering where it went.

Answer 16

I'm sorry,i'll redo it.Thanks for being patient, heh.

Answer 17

no problem :)

Answer 18

\[\sqrt{486}-\sqrt{24}+\sqrt{6}\]write out the multiples of each first. \[\sqrt{18*27}-\sqrt{6*4}+\sqrt{3*2}\] see if you can pull our any pairs of numbers, if not, simplify further.\[\sqrt{3*3*2}-\sqrt{3*2*2*2}+\sqrt{3*2}\]

Answer 19

I think its 8 sqrt 6

Answer 20

right ?

Answer 21

sorry, \[\sqrt{18*27}= \sqrt{3*3*2*3*3*3}= 9\sqrt{6}\] ****

Answer 22

yes! you are right.

Answer 23

thank u:)

Answer 24

haha np x_x