Question

Is a copper pipe consider to be a "closed" circuit?

Answer 1

Where Lenz's law is applied, when a magnet passes through a copper pipe, current is induced, and a magnetic field is created to oppose the magnet that created it.However, in a open circuit I = 0, thus there is no magnetic field, thus the magnet passes through it with no resistance. The only resistance acting on the magnet is friction?

Answer 2

Im guessing since a copper pipe is closed... Current can flow.
And it cylinder shaped...
Lenz law is effective and eddy current are generated to oppose the magnet.
But in a coil that's circuit is open current can't flow, thus there is no magnetic field.

Answer 3

@Vincent-Lyon.Fr
@Jemurray3
@ghazi @Shane_B @TuringTest

Answer 4

All you have to know that is that current will flow at all. If it down then there must be a "closed" circuit.

Answer 5

@Eleven17 so, a copper pipe is indeed a "closed" circuit.
But if it was "open" like a coil in a "opened" circuit there will be no flow of current.

Answer 6

first of all i would suggest you to think of circuit, what exactly circuit means then i am sure you wont think of copper pipe as circuit anymore :), if you think of it as a circuit can you state how?? it is not a circuit , current will flow from a low potential end to the high potential end across the pipe but , if you just think of pipe then its not a circuit. by the way its good to know you wonder about things and never let this thing go, keep wondering keep finding :D current will flow across the surface from the terminals of potential difference