Mathematics
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OpenStudy (anonymous):
Find the product of (2x + 5y)^2.
4x^2 + 20xy + 25y^2
4x^2 − 20xy + 25y^2
4x^2 − 25y^2
4x^2 + 25y^2
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
(2x + 5y)^2
(2x + 5y)(2x + 5y)
2x(2x + 5y) + 5y(2x + 5y)
I'll let you finish up
OpenStudy (luigi0210):
darn it -_-
jimthompson5910 (jim_thompson5910):
you're on the right track Luigi0210, it should be a^2 + 2ab + b^2 though
OpenStudy (luigi0210):
Yea, just noticed that.. thanks for the correction
jimthompson5910 (jim_thompson5910):
np
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jimthompson5910 (jim_thompson5910):
2x(2x + 5y)
turns into
2x*2x + 2x*5y
and that turns into
4x^2 +10xy
jimthompson5910 (jim_thompson5910):
the second bit 5y(2x + 5y) is simplified the same way
jimthompson5910 (jim_thompson5910):
5y*5y is NOT 25y
but it's actually ______
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OpenStudy (anonymous):
I don't know what it would be > . < 5 * 5 is 25
jimthompson5910 (jim_thompson5910):
that part is correct, but y times y is not y
jimthompson5910 (jim_thompson5910):
y times y = ______
OpenStudy (anonymous):
Oh, 25y^2?
jimthompson5910 (jim_thompson5910):
yep, now combine like terms
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OpenStudy (anonymous):
@jim_thompson5910 am I correct?
jimthompson5910 (jim_thompson5910):
close, but 10xy plus 10xy is 20xy and the 20 is positive
OpenStudy (anonymous):
So, the first one?
jimthompson5910 (jim_thompson5910):
correct